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phadej
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Jul 26, 2021
phadej
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Jul 26, 2021
phadej
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Jul 26, 2021
| start = Scanr1 $ \_ -> VNil | ||
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| step :: forall m. N.SNatI m => Scanr1 m a -> Scanr1 ('S m) a | ||
| step (Scanr1 go) = Scanr1 $ \(x ::: xs) -> case N.snat :: N.SNat m of |
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This doesn't feel right. You shouldn't need to check length in the step case. I can take a look myself if you cannot find a way to avoid it.
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In scanr1, the last element is special (it is the zero element), and so the 0 -> 1 step and the m -> m + 1 step (where m > 0) are different. But yeah please let me know if there's a better way to write this.
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@phadej - let me know if you have any updates on this!
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Fixes #90