Possible issue.

[DmytroHubernatorov]

API_Examples/Workflow_via_CSV/initTemplate.py

Line 54 in 2d9b8fe

f = open('{}{}.txt'.format(workflow_name, i), 'w')

In case of intensive usage it will not guarantee file name will be 'engaged' by another process.
There are functions for unique file name creation.
Or update implementation like - try to create file name and grab it.